Click here??to get an answer to your question ?? Show that f(x) = x^1/3 is not differentiable at x = 0 .The function x1/3 is not differentiable at x=0, but the graph {(x,x1/3):x?R}?R2 is a smooth submanifold, something that for example does. UPLOAD PHOTO AND GET THE ANSWER NOW! Text Solution. Solution : Given function,

`f(x)=x^(1//3)`

we know that. For the differentiability, LHD (at x = 0) = RHD (at x = 0). = Not defined the value. = Not defined the value. Here, LHD and RHD does not. 3. The graph has a vertical line at the point. 1. Page 2. Example 1: H(x) =. 0 x < 0. 1 x ? 0. H is not continuous at 0, so it is not differentiable at 0.

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## show that f(x)=x^1/3 is not differentiable at x=0

UPLOAD PHOTO AND GET THE ANSWER NOW! Text Solution. Solution : Given function,

`f(x)=x^(1//3)`

we know that. Example: The function f(x) = |x| (absolute value):. At x=0 the derivative is undefined, so x(1/3) is not differentiable, unless we exclude x=0.For the differentiability, LHD (at x = 0) = RHD (at x = 0). = Not defined the value. = Not defined the value. Here, LHD and RHD does not. Show Solution. Disclaimer: It might be a wrong question because f(x) is differentiable at x=0. Given: f ( x ) = x 1 3. We have, (LHD at x = 0).Assume f?(0) exists. Consider g(x)=(f(x))3=x.Then by the chain rule g?(0)=3(f(0))2f?(0). Since g?(0)=1 and f(0)=0, we find 1=0?f?(0),

## prove that x 1 3 is not differentiable

Show that F(X) = X1/3 is Not Differentiable at X = 0. Show Solution. Disclaimer: It might be a wrong question because f(x) is differentiable at x=0.does not exist. Example 8.8. The function f : R ? R defined by f(x) = x1/3 is differentiable at x = 0 with f (x) = 1. 3×2/3. To prove this result, UPLOAD PHOTO AND GET THE ANSWER NOW! Text Solution. Solution : Given function,

`f(x)=x^(1//3)`

we know that. For example the absolute value function is actually continuous (though not differentiable) at x=0. Question 1 Question 2 Question 3 Question 4 Question 5. For the differentiability, LHD (at x = 0) = RHD (at x = 0). = Not defined the value. = Not defined the value. Here, LHD and RHD does not.

## is x^1/3 continuous at 0

L.H.L is not equal to R.H.L at x=0. So, function is not continuous at x=0. Option C is correct. Solve any question of Continuity and Differentiability with. No, it is not continuous at x=3 since it is not defined there (zero denominator). values of x for which the function g(x)=(sin(x20+5))13 is continuous?Click here??to get an answer to your question ?? Prove that the function f(x) = 5x – 3 is continuous at x = 0 , at x = – 3 and at x = 5 .But a function can be continuous but not differentiable. For example the absolute value function is actually continuous (though not differentiable) at x=0.is not continuous at a because underset{xto a}{lim}f(x). is continuous at 0, we may apply the composite function theorem. It begins at (1,3).>.

## show that f r ? r f x x 1 3 is not a differentiable function

For the differentiability, LHD (at x = 0) = RHD (at x = 0). = Not defined the value. = Not defined the value. Here, LHD and RHD does not. 1. 3×2/3. To prove this result, we use the identity for the difference of cubes, 1. 3c2/3. However, f is not differentiable at 0, since lim h?0.UPLOAD PHOTO AND GET THE ANSWER NOW! Text Solution. Solution : Given function,

`f(x)=x^(1//3)`

we know that. For example the absolute value function is actually continuous (though not differentiable) at x=0. Question 1 Question 2 Question 3 Question 4 Question 5. Click here??to get an answer to your question ?? Show that f(x) = x^1/3 is not differentiable at x = 0 .