# If r and s are two solutions of the equation

2x^2+7x-15=0If r and s are two solutions of the equation above and r > s, which of the following is the value of r-s? 1. See answer. plus. Add answer+5 pts.2×2 + 7x ? 15 = 0. If r and s are two solutions of the equation above and r > s, which of the following is the value of r ? s? A) 15/2.Answer: 6.5. Split the middle term into two terms:2 x2 – 3 x + 10 x – 15 = 0Factor the first two terms and the la.When a line passes through the origin, all of the points on the line (other than the origin) tell you the slope. So the answer here is 3/8.Answer: 3. Rearrange all nonzero terms to the left side of the equation:x2 – 3 x – 28 = 0Split the middle term.

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## in the xy plane if the parabola with equation y=ax2+bx+c

In the xy-plane, if the parabola with equation y=ax2+bx+c , where a, b, and c are constants,, passes through the point -1,1 , which of the. In case of a parabola(quadratic expression) ax^2 + bx + c: If parabola intersects x-axis at two distinct points, it means the quadratic. In the xy-plane, if the parabola with equation y=ax2+bx+c, , where a, b, and c are constants,, passes through the point -1,1 I, which of the. Transcribed image text: In the xy-plane, if the parabola with equation y = ax2 + bx + c, where a, b, and c are constants, passes through the point (-1,1), In the xy-plane, if the parabola wiry equation y=ax^2+bx+c, where a, b, and c are constants, passes through the point (-1,1), which of the.

## if p and q are distinct roots of the equation above and pq > 0, what is the value of the product pq?

Now if p = q, then the first equation gives (a + b)p = 1 and the second gives. We therefore deduce that aq = ±bp, which we can divide by pq = 0 to get a.Show that the product of these roots is. 2. 2. 1. 2. p q. roots of the above given equation, find the value of P and the value of Q. SPX-K , 0. P = ,For an equation , a^2+bx+c=0 sum of roots = -b/a product of roots = c/a. Hence here p+q =-p pq=q solving we will get p=0, q=0, p=1, q= -2Now take any x > 0 and set p = x, q = 1, r = s = ?x to obtain. The equation has as many as four variables with only one constraint pq = rs, leaving.The following would work if we are strictly dealing with the integral domain. Let’s start from the root! 😛 A quadratic equation with distinct roots can be.

## to cut a lawn, allan charges

To cut a lawn, Allan charges a fee of (\$15) for his equipment and (\$8.50) per hour spent cutting a lawn. Taylor charges a fee of (\$12) for his. To cut a lawn, Allan charges a fee of \$15 for his equipment and \$8.50 per hour spent cutting a lawn. Taylor charges a fee of \$12 for his equipment and \$9.25. Transcribed image text: 7 To cut a lawn, Allan charges a fee of \$15 for his equipment and \$8.50 per hour spent cutting a lawn. Taylor charges a fee of \$12. To cut a lawn, Allan charges a fee of \$15 for his equipment and \$8.50 per hour spent cutting a lawn. ‘laylor charges a fee of \$12 for his equipment and.To cut a lawn, Allan charges a fee of 15forhisequipmentand8.50 per hour spent cutting a lawn. Taylor charges a fee of 12forhisequipmentand9.25 per hour.

## the equation above is used to model the relationship

n=456-3T The equation above is used to model the relationship between the number of cups, n, of hot chocolate sold per day in a coffee shop and. T=25+3c The equation above is used to model the number of chirps, c, made by a certain species of cricket in one minute, and the temperature. n=456-3T The equation above is used to model the relationship between the number of cups, n, of hot chocolate sold per day in a coffee shop. The equation above is used to model the relationship between the number of cups, n, of hot chocolate sold per day in a coffee shop and the average daily. (n=456-3T) The equation above is used to model the relationship between the number of cups, (n), of hot chocolate sold per day in a coffee shop and the.