# Find three consecutive integers whose sum is 51

Which means that the first number is 16, the second number is 16 + 1 and the third number is 16 + 2. Therefore, three consecutive integers that add up to 51 are. Explanation: 51÷3=17 16,17,18 x+(x+1)+(x+2)=51?x=16.Complete step-by-step answer: Let the first number be x. Then as all the three given numbers are consecutive, then the next two numbers will be x + 1 and x. Answer is 15, 17 and 19. How? Divide 51 by 3 and you get 17, which is an odd number. That is the second odd number. So, deduct 2 to get. find three consecutive integers whose sum is 51. Answer provided by our tutors. The three consecutive integers can be written as: x – 1, x and x + 1,

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## find three consecutive integers if the sum of the first two is 51 more than the third integer

Let the first integer be x. Then the next consecutive two integers will be x + 1 and x + 2. x + (x + 1) + (x + 2) = 51 [Sum of the 3 consecutive integers is. The sum of a positive integer and a negative integer is always positive. Answer by Fombitz (32382) ( Show Source ): You can put this solution on YOUR website!Question 273359: There is three consecutive positive integers. if the square of the third integer is 51 more than the sum of the first two what are the integers. The sum of three consecutive even integers is 108. odd integers are separated by two, each consecutive odd integer is two larger than the one before it.Question 158837: Find three consecutive integers if the sum of the first two integers is 6 more than the third integer. Answer by nabla(475) · About Me.

## the sum of three consecutive multiples of 8 is 888 find the multiples

So the three consecutive multiples you are looking for are 36*8 =288, 37*8 = 296 and 37*8 = 304.Therefore, the three consecutive multiples of 8 whose sum is 888 are 288, 296 and 304. acobdarfq and 17 more users found. The sum of three consecutive multiples of 8 is 888. Find the multiples · 8p  8 = 296  8 = 288 · 8p = 296 · 8p + 8 = 296 + 8 = 304.Let 8n be the first multiple. Then the next multiple would be 8(n+1), and then 8(n+2). So: 8n+8(n+1)+8(n+2)=888 24n+24=888 24n=864 n=36 Then, the multiples. The sum of three consecutive multiples of 8 is 888. Find the multiples. · (x+1) · (x+2) · 8x+8(x+1)+8(x+2)=888 · 8x+8x+8x+8+16=888 · 24x+24=888 · 24x=888?24 · 24x=864.

## three consecutive positive integers

Three consecutive positive integers are such that the sum of the square of the first and the product of the other two is 46. Find the integers.Originally Answered: three consecutive positive integers and the product of the larger two integers is four more than twice the smallest integer. What is. Three consecutive positive integers are such that the sum of the square of the first and the product of other two is 46, find the integers.Three consecutive positive integers are such that the sum of the square of the first and product of the other two is 46. Find the integers.Answer: Out of any three consecutive positive integers only one number is divisible by 3. The proof is given below. case1: if n is a multiple of 3. n = 3q n +.